P(E) ~= 1 | C (where “|” stands for “given”). If I can say this, I can most certainly say that C causes E
Well… unless P(E) also ~= 1 | !C because P(E) ~= 1 and C is irrelevant
Corrected the wording to be a bit “weaker” on that claim, but also, it’s just a starting point and the final definition I dispute against doesn’t rest on it.
Well… unless P(E) also ~= 1 | !C because P(E) ~= 1 and C is irrelevant
Corrected the wording to be a bit “weaker” on that claim, but also, it’s just a starting point and the final definition I dispute against doesn’t rest on it.