Would they look so precisely exponential, with exactly the same exponent, if we fit 5-10 log-linear lines to the graph rather than one? Eyeballing it, looks like the answer is no...
Of course other log-linear lines would pass closer to some of the points. The fact to be explained is that you can get a ridiculously low-mean-squared-error fit with one log-linear line.
Would they look so precisely exponential, with exactly the same exponent, if we fit 5-10 log-linear lines to the graph rather than one? Eyeballing it, looks like the answer is no...
Of course other log-linear lines would pass closer to some of the points. The fact to be explained is that you can get a ridiculously low-mean-squared-error fit with one log-linear line.
Sorry, what do you mean?