According to my understanding, you start out knowing that v(A) = v(1) for a particular interpretation v.
If v is an interpretation, it maps (all) terms to elements of corresponding universe, while possible actions are only some formulas, so associated mapping K would map some formulas to the set of actions (which don’t have to do anything with any universe). So, we could say that K(1)=1′, but K(A) is undefined. K is not an interpretation.
If v is an interpretation, it maps (all) terms to elements of corresponding universe, while possible actions are only some formulas, . . .
Maybe we’re not using the terminology in exactly the same way.
For me, an interpretation of a theory is an ordered pair (D, v), where D is a set (the domain of discourse), and v is a map (the valuation map) satisfying certain conditions. In particular, D is the codomain of v restricted to the constant symbols, so v actually contains everything needed to recover the interpretation. For this reason, I sometimes abuse notation and call v itself the interpretation.
The valuation map v
maps constant symbols to elements of D,
maps n-ary function symbols to maps from D^n to D,
maps n-ary predicate symbols to subsets of D^n,
maps sentences of the theory into {T, F}, in a way that satisfies some recursive rules coming from the rules of inference.
Now, in the post, you write
Each such statements defines a possible world Y resulting from a possible action X. X and Y can be thought of as constants, just like A and O, or as formulas that define these constants, so that the moral arguments take the form [X(A) ⇒ Y(O)].
(Emphasis added.) I’ve been working with the bolded option, which I understand to be saying that A and 1 are constant symbols. Hence, given an interpretation (D, v), v(A) and v(1) are elements of D, so we can ask whether they are the same elements.
K has a very small domain. Say, K(“2+2”)=K(“5″)=”pull the second lever”, K(“4”) undefined, K(“A”) undefined. Your v doesn’t appear to be similarly restricted.
If v is an interpretation, it maps (all) terms to elements of corresponding universe, while possible actions are only some formulas, so associated mapping K would map some formulas to the set of actions (which don’t have to do anything with any universe). So, we could say that K(1)=1′, but K(A) is undefined. K is not an interpretation.
Maybe we’re not using the terminology in exactly the same way.
For me, an interpretation of a theory is an ordered pair (D, v), where D is a set (the domain of discourse), and v is a map (the valuation map) satisfying certain conditions. In particular, D is the codomain of v restricted to the constant symbols, so v actually contains everything needed to recover the interpretation. For this reason, I sometimes abuse notation and call v itself the interpretation.
The valuation map v
maps constant symbols to elements of D,
maps n-ary function symbols to maps from D^n to D,
maps n-ary predicate symbols to subsets of D^n,
maps sentences of the theory into {T, F}, in a way that satisfies some recursive rules coming from the rules of inference.
Now, in the post, you write
(Emphasis added.) I’ve been working with the bolded option, which I understand to be saying that A and 1 are constant symbols. Hence, given an interpretation (D, v), v(A) and v(1) are elements of D, so we can ask whether they are the same elements.
I agree with everything you wrote here...
What was your “associated mapping K”? I took it to be what I’m calling the valuation map v. That’s the only map that I associate to an interpretation.
K has a very small domain. Say, K(“2+2”)=K(“5″)=”pull the second lever”, K(“4”) undefined, K(“A”) undefined. Your v doesn’t appear to be similarly restricted.