lucidfox comments on Looking for proof of conditional probability

lucidfox 29 Jul 2011 6:26 UTC
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and P(A|C)/P(B|C) = P(A)/P(B) when A and B are subsets of C?

When A is a subset of C, P(A|C) = P(A).
- Oscar_Cunningham 29 Jul 2011 7:03 UTC
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  Parent
  Um, no?
  - lucidfox 29 Jul 2011 8:16 UTC
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    Parent
    ...Oops, yes, said that without thinking. But this
    
    Basically, P(A|B) = 0 when A and B are disjoint, and P(A|C)/P(B|C) = P(A)/P(B) when A and B are subsets of C?
    
    is correct.