It’s not entirely clear what you’re saying, but I’ll try to take the simplest interpretation. I’m guessing that:
If you’re going to defect, your clone always defects.
If you’re going to cooperate, your clone cooperates with probability 1-p and defects with probability p
In that case, I don’t see how it is that you get “defect” for p>0; the above formulation gives “cooperate” for 0<=p<0.5.
It’s not entirely clear what you’re saying, but I’ll try to take the simplest interpretation. I’m guessing that:
If you’re going to defect, your clone always defects.
If you’re going to cooperate, your clone cooperates with probability 1-p and defects with probability p
In that case, I don’t see how it is that you get “defect” for p>0; the above formulation gives “cooperate” for 0<=p<0.5.