More generally, the discipline of decision theory is not about figuring out the right solution to a particular problem—it’s about describing the properties of decision methods that reach the right solutions to problems generally.
Newcomb’s is an example of a situation where some decision methods (eg CDT) don’t make what appears to be the right choice. Either CDT is failing to make the right choice, or we are not correctly understanding what the right choice is. That dilemma motivates decision-theorists, not particular solutions to particular problems.
That’s possible, but I am not sure how I am fighting it in this case. Leave Omega in place- why do we assume equal probability of omega guessing incorrectly or correctly, when the hypothetical states he has guessed correctly each previous time? If we are not assuming that, why does cdc treat each option as equal, and then proceed to open two boxes?
I realize that decision theory is about a general approach to solving problems- my question is, why are we not including the probability based on past performance in our general approach to solving problems, or if we are, why are we not doing so in this case?
No. I think that is fighting the hypothetical.
More generally, the discipline of decision theory is not about figuring out the right solution to a particular problem—it’s about describing the properties of decision methods that reach the right solutions to problems generally.
Newcomb’s is an example of a situation where some decision methods (eg CDT) don’t make what appears to be the right choice. Either CDT is failing to make the right choice, or we are not correctly understanding what the right choice is. That dilemma motivates decision-theorists, not particular solutions to particular problems.
That’s possible, but I am not sure how I am fighting it in this case. Leave Omega in place- why do we assume equal probability of omega guessing incorrectly or correctly, when the hypothetical states he has guessed correctly each previous time? If we are not assuming that, why does cdc treat each option as equal, and then proceed to open two boxes?
I realize that decision theory is about a general approach to solving problems- my question is, why are we not including the probability based on past performance in our general approach to solving problems, or if we are, why are we not doing so in this case?