Note that the normalisation procedure leads to being on the fence between C and D at p = 2⁄3.
If I’m correct in my ad-hoc approach to calculating the NBS when p = 2⁄3, then this is firmly in the territory which prefers D to C. Therefore the parliamentary model gives different solutions to any normalisation procedure.
Note that the normalisation procedure leads to being on the fence between C and D at p = 2⁄3.
If I’m correct in my ad-hoc approach to calculating the NBS when p = 2⁄3, then this is firmly in the territory which prefers D to C. Therefore the parliamentary model gives different solutions to any normalisation procedure.