Peter_de_Blanc comments on No Universal Probability Space

Peter_de_Blanc 7 May 2009 22:38 UTC
4 points

probability measure P on the measurable space ({heads, tails}, {{}, {heads}, {tails}, {heads, tails}}), P({heads}) = P({tails}) = ¹⁄₂ and P({}) = P({heads, tails}) = 0

I think you mean P({heads, tails}) = 1.
- Gordon Seidoh Worley 8 May 2009 4:51 UTC
  0 points
  Parent
  Wow, that’s a pretty bad error to miss. Fixed.
  - Gordon Seidoh Worley 8 May 2009 5:24 UTC
    1 point
    Parent
    The more I think about it, the sadder it is that it took LW a day and a half to catch that error.