I puted no such diagram
I thought you had because you said
If you treat P ⇔ (Q ⇔ P) as an acausal statement, you can show its equivalence to Q, but it is not the same causal network.
I took this to mean that you were treating P ⇔ (Q ⇔ P) and Q as causal networks, but distinct ones.
You also said
I can set P.
I took this to mean that P was an exogenous variable in a causal network.
I apologize for the misinterpretation.
I thought you had because you said
I took this to mean that you were treating P ⇔ (Q ⇔ P) and Q as causal networks, but distinct ones.
You also said
I took this to mean that P was an exogenous variable in a causal network.
I apologize for the misinterpretation.