Actually, I realise that you can get around this. If you use a decision theory that assumes that you are deciding for all identical copies of you, but that you can’t affect the choices of copies that has diverged from you in any way, math says you will always bet correctly.
Actually, I realise that you can get around this. If you use a decision theory that assumes that you are deciding for all identical copies of you, but that you can’t affect the choices of copies that has diverged from you in any way, math says you will always bet correctly.
Yes, that is shown in Part 2.