Assuming 10^6 bit erasures per FLOP (as you did; which source are you using?), one only needs 8.06*10^13 kWh (= 2.9*10^(-21)*10^(35+6)/(3.6*10^6)), i.e. 2.83 (= 8.06*10^13/(2.85*10^13)) times global electricity generation in 2022, or 18.7 (= 8.06*10^13/(4.30*10^12)) times the one generated in the United States.
Hi there,
Assuming 10^6 bit erasures per FLOP (as you did; which source are you using?), one only needs 8.06*10^13 kWh (= 2.9*10^(-21)*10^(35+6)/(3.6*10^6)), i.e. 2.83 (= 8.06*10^13/(2.85*10^13)) times global electricity generation in 2022, or 18.7 (= 8.06*10^13/(4.30*10^12)) times the one generated in the United States.