I don’t think it’s quite the same. The underlaying mathematics are the same, but this version side-steps the philosophical and game-theoretical issues with the other (namely, acausal behaviour).
Incidentally; If you take both boxes with probability p each time you enter the room, then your expected gain is p1000 + (1-p) 1000000. For maximum gain, take p=0; i.e. always take only box B.
I don’t think it’s quite the same. The underlaying mathematics are the same, but this version side-steps the philosophical and game-theoretical issues with the other (namely, acausal behaviour).
Incidentally; If you take both boxes with probability p each time you enter the room, then your expected gain is p1000 + (1-p) 1000000. For maximum gain, take p=0; i.e. always take only box B.
EDIT: Assuming money is proportional to utility.