In the infinite limit (or just large-ish x), the probability of at least one success, from nx attempts with 1/x odds on each attempt, will be 1 - ( 1 / e^n )
For x attempts, 1 − 1/e = 0.63212
For 2x attempts 1 − 1/e^2 = 0.86466
For 3x attempts 1 − 1/e^3 = 0.95021
And so on
In the infinite limit (or just large-ish x), the probability of at least one success, from nx attempts with 1/x odds on each attempt, will be 1 - ( 1 / e^n )
For x attempts, 1 − 1/e = 0.63212
For 2x attempts 1 − 1/e^2 = 0.86466
For 3x attempts 1 − 1/e^3 = 0.95021
And so on