if you really care about the values on that list, then there are linear aggregations
Of course existence doesn’t mean that we can actually find these coefficients. Even if you have only 2 well-defined value functions, finding an optimal tradeoff between them is generally computationally hard.
Of course existence doesn’t mean that we can actually find these coefficients. Even if you have only 2 well-defined value functions, finding an optimal tradeoff between them is generally computationally hard.