The equipment is already calibrated. You have said that everything works in the same way as today, except the universe consists of two planets. Which I have interpreted like that the observer already knows the value of the gravitational constant in units he can use. If the gravitational constant has to be independently measured first, then it is more complicated, of course.
The equipment is already calibrated. You have said that everything works in the same way as today, except the universe consists of two planets.
Right: you know the laws of physics. You don’t know your mass though, and you don’t know any object that has a known mass. I posit this because, in the history of science, they made certain measurements that aren’t possible in a two-planet universe, and to assume you can calibrate to those measurements would assume away the problem.
But still, in the rotating scenario the attractive force wouldn’t be perpendicular to the planet’s surface, and this can be established without knowing the gravitational constant. If the planet is spherical and you already know what is perpendicular, of course.
Calculate the gravitational force on the surface of a planet of the same size and mass as yours and compare with what you actually measure.
What do you calibrate your equipment against?
The equipment is already calibrated. You have said that everything works in the same way as today, except the universe consists of two planets. Which I have interpreted like that the observer already knows the value of the gravitational constant in units he can use. If the gravitational constant has to be independently measured first, then it is more complicated, of course.
Right: you know the laws of physics. You don’t know your mass though, and you don’t know any object that has a known mass. I posit this because, in the history of science, they made certain measurements that aren’t possible in a two-planet universe, and to assume you can calibrate to those measurements would assume away the problem.
But still, in the rotating scenario the attractive force wouldn’t be perpendicular to the planet’s surface, and this can be established without knowing the gravitational constant. If the planet is spherical and you already know what is perpendicular, of course.