I recall estimating the power required to run an equatorial superconducting ring a few meters thick 1 km or so under the Mars surface with enough current to simulate Earth-like magnetic field. If I recall correctly, it would require about the current level of power generation on Earth to ramp it up over a century or so to the desired level. Then whatever is required to maintain it (mostly cooling the ring), which is very little. Of course, an accident interrupting the current flow would be an epic disaster.
Let’s do a quick estimate. Destroying a Mars-like planet requires expending the equivalent of its gravitational self-energy, ~GM^2/R, which is about 10^32J (which we could easily obtain from a comet 10 kn in radius… consisting of antimatter!) For comparison, the Earth’s magnetic field has about 10^26J of energy, a million times less. I leave it to you to draw the conclusions.
I recall estimating the power required to run an equatorial superconducting ring a few meters thick 1 km or so under the Mars surface with enough current to simulate Earth-like magnetic field. If I recall correctly, it would require about the current level of power generation on Earth to ramp it up over a century or so to the desired level. Then whatever is required to maintain it (mostly cooling the ring), which is very little. Of course, an accident interrupting the current flow would be an epic disaster.
Wouldn’t it be more efficient to use that energy to destroy Mars and build start building a Dyson swarm from the debris?
Let’s do a quick estimate. Destroying a Mars-like planet requires expending the equivalent of its gravitational self-energy, ~GM^2/R, which is about 10^32J (which we could easily obtain from a comet 10 kn in radius… consisting of antimatter!) For comparison, the Earth’s magnetic field has about 10^26J of energy, a million times less. I leave it to you to draw the conclusions.