Wow, this is honestly baffling. It sounds as if Deutsch doesn’t know about the generalised form of Bayes’ theorem (I’m sure he does know, which makes me feel worse).
P(Hi|E)=P(E|Hi)P(Hi)ΣjP(E|Hj)P(Hj)
You make an excellent point. Bayes’ theorem can be applied to all possible hypotheses, not just H and ¬H.
If a top physicist can be this biased, then I cannot be surprised by anything anymore.
Wow, this is honestly baffling. It sounds as if Deutsch doesn’t know about the generalised form of Bayes’ theorem (I’m sure he does know, which makes me feel worse).
P(Hi|E)=P(E|Hi)P(Hi)ΣjP(E|Hj)P(Hj)You make an excellent point. Bayes’ theorem can be applied to all possible hypotheses, not just H and ¬H.
If a top physicist can be this biased, then I cannot be surprised by anything anymore.
Thank you very much for your response Yoav Ravid.