Assuming a >0 value density throughout the universe, then an infinite space will contain infinite value as no matter how small you make the value density, the universe is infinitely large, so no matter how much value you want, you can just look further out and consider a larger space that will contain as much value as needed, ad infinitum.
You are simply wrong about the math there. I can construct an infinite sequence of terms >0 which sum to a finite number.
sum_{nrightarrowinfty}{n=1}1/2n=1
If you meant that there is some sigma, such that every X-large portion of the universe had value of at least sigma, you would be technically correct. You are already setting a lower bound on value, which precludes the possibility of there being an x-large area of net negative value.
Your math looks wrong. The sum from 1 to infinity of 1/n does not converge, and as a simple visualization 1 + 1⁄2 + 1⁄3 + 1⁄4 is already greater than 2.
You are simply wrong about the math there. I can construct an infinite sequence of terms >0 which sum to a finite number.
sum_{nrightarrowinfty}{n=1}1/2n=1
If you meant that there is some sigma, such that every X-large portion of the universe had value of at least sigma, you would be technically correct. You are already setting a lower bound on value, which precludes the possibility of there being an x-large area of net negative value.
EDIT: Corrected from 1/n to 1/2^n
Your math looks wrong. The sum from 1 to infinity of 1/n does not converge, and as a simple visualization 1 + 1⁄2 + 1⁄3 + 1⁄4 is already greater than 2.
Brainfart: My math was wrong. Corrected to 1/n^2
That’s 1/2+1/4+1/8… or Zeno’s sum.