If you don’t think that this assumption is appropriate, you can suggest some other model and do a calculation. One thing I can guarantee you is that it won’t produce the number 1⁄3.
I think you’re missing the point. The effect size of the gene or genes is irrelevant, as is the architecture. There can be any distribution as long as there’s enough to be consistent with current genetic research on homosexuality having turned up few or no hits (linkage, 23andMe’s GWAS & GCTA, etc). The important question is merely: do their sisters have enough kids to via inclusive fitness make up for their own lack of kids? If the answer is no, you’re done with the sexual antagonism theory, so you only need to detect that. This is set by the fitness penalty of being homosexual, not by any multiplications. So if homosexuals have 1 fewer kid, then you need to detect 2 kids among their sisters, and so on. From that you do the power calculation.
So if homosexuals have 1 fewer kid, then you need to detect 2 kids among their sisters, and so on. From that you do the power calculation.
Back when you did the power calculation for 1⁄3 rather than 2, you didn’t believe that. This number 2 is wrong for three reasons:
Inclusive fitness is irrelevant to the antagonistic selection hypothesis. (factor of 2)
It ignores penetrance, which is clearly not 100%; it doesn’t matter how many children homosexuals have, but rather how many children (male) carriers of the gene(s) have. (factor of 3)
It ignores the fact that siblings only are only 1⁄2 related. The relevant gene(s) should only elevate the fertility of carriers, not all sisters. (factor of 2)
I think you’re missing the point. The effect size of the gene or genes is irrelevant, as is the architecture. There can be any distribution as long as there’s enough to be consistent with current genetic research on homosexuality having turned up few or no hits (linkage, 23andMe’s GWAS & GCTA, etc). The important question is merely: do their sisters have enough kids to via inclusive fitness make up for their own lack of kids? If the answer is no, you’re done with the sexual antagonism theory, so you only need to detect that. This is set by the fitness penalty of being homosexual, not by any multiplications. So if homosexuals have 1 fewer kid, then you need to detect 2 kids among their sisters, and so on. From that you do the power calculation.
Back when you did the power calculation for 1⁄3 rather than 2, you didn’t believe that. This number 2 is wrong for three reasons:
Inclusive fitness is irrelevant to the antagonistic selection hypothesis. (factor of 2)
It ignores penetrance, which is clearly not 100%; it doesn’t matter how many children homosexuals have, but rather how many children (male) carriers of the gene(s) have. (factor of 3)
It ignores the fact that siblings only are only 1⁄2 related. The relevant gene(s) should only elevate the fertility of carriers, not all sisters. (factor of 2)