It’s a small thing, but 10 bits allows you to count 1024 total chambers, not 1025. They’ll be numbered from 0 to 1023 if you translate the bitstring directly into decimal numbers. Similar to how two digits in decimal lets you count from 0 to 99, but 100 requires a third digit.
It’s a small thing, but 10 bits allows you to count 1024 total chambers, not 1025. They’ll be numbered from 0 to 1023 if you translate the bitstring directly into decimal numbers. Similar to how two digits in decimal lets you count from 0 to 99, but 100 requires a third digit.
Well that’s a tad embarrassing. Thanks for pointing it out! I made the edit.