Here are some ways to get more strict inequalities (less incomparability or equivalence):
1. Require q=1−p to handle some more cases with both positive and negative expected infinities, but I’m not sure that the results would always be intuitive. There might be other relationships between p and q that that depend on the particular lotteries that work better. You could test the lim infs under multiple relationships, q=1−f(p) for different f from a specific set.
Here are some ways to get more strict inequalities (less incomparability or equivalence):
1. Require q=1−p to handle some more cases with both positive and negative expected infinities, but I’m not sure that the results would always be intuitive. There might be other relationships between p and q that that depend on the particular lotteries that work better. You could test the lim infs under multiple relationships, q=1−f(p) for different f from a specific set.
2. Replace the strict inequality condition with
lim(p,q)→(0,1),0<p<q<1sgn(∫qpQU(B)(t)−QU(A)(t)dt)=1.Equivalently, there are p0,q0,0<p0<q0<1 such that ∫qpQU(B)(t)−QU(A)(t)>0 for all p,q,0<p<p0<q0<q<1.
A<B would mean that the integral for A never catches up with that for B in the limit.