Can you elaborate?
Markov’s inequality says that, if 0 ⇐ X ⇐ 1, then
P[X >= a] ⇐ E[X] / a
and that
P[X ⇐ a] ⇐ E[1-X] / (1-a)
These are directional statements, hence directionality of metaconfidence.
Can you elaborate?
Markov’s inequality says that, if 0 ⇐ X ⇐ 1, then
P[X >= a] ⇐ E[X] / a
and that
P[X ⇐ a] ⇐ E[1-X] / (1-a)
These are directional statements, hence directionality of metaconfidence.