I couldn’t decide exactly you meant by “twice as likely to be asked (woken) when it’s tails” either. I’m going to guess that you’re averaging evenly over Monday and Tuesday, in which case I agree. After marginalizing over M/T, P(wake|heads)=1/2 and P(wake|tails)=1.
I couldn’t decide exactly you meant by “twice as likely to be asked (woken) when it’s tails” either. I’m going to guess that you’re averaging evenly over Monday and Tuesday, in which case I agree. After marginalizing over M/T, P(wake|heads)=1/2 and P(wake|tails)=1.