I think my answer is actually equivalent to Nornagest’s.
The obvious answer is that the factors you divide by are (0.9 / 0.5) and (0.1 / 0.5), which results in the same expected value as the pre-arranged calculation.
I think my answer is actually equivalent to Nornagest’s.
The obvious answer is that the factors you divide by are (0.9 / 0.5) and (0.1 / 0.5), which results in the same expected value as the pre-arranged calculation.