“Can’t do basic derivatives?
Seriously?!?
I’m for kicking the troll out.
His bragging about mediocre mathematical accomplishments isn’t informative or entertaining to us readers.”
Did you look at his derivatives? “dy/dt = F(y) = Ay whose solution is y = e^(At)” How is e^(at) = dy/dt=ay
Basic derivatives 101 d/dx e^x = e^x
“Solving
dy/dt = e^y
yields
y = -ln(C—t)”
again dy/dt=e^y does not equal -ln(c-t) unless e is not the irrational constant that it is normally even if that it is the case the solution is still wrong… again refer to a basic derivative table...
So I am a troll because I point out errors? Ok, fine then I am a troll and will never come back. Thats interesting so you must be a saint for thinking these errors are the truth.
I apologize that I am not amusing you, but I am not a court jester like yourself.
Mediocre accomplishments hmm… well did you skip all of your bachelors work straight to grad school in mathematics? I would bet not. Don’t talk of mediocrity unless you can prove yourself above that standard. So I believe your credentials would be needed to prove that or some of your own superior accomplishments if you have any? I await eagerly.
I believe that GenericThinker is interpreting ‘dy/dt = e^y’ as instructions to take the derivative of e^y (with respect to y or t I’m not sure). This is an extreme (and extremely arrogant) case of a general problem in lower-level and non-major math education; students learn to treat ‘=’ as a generic verb (although here it’s more of a preposition) instead of a symbol with a specific meaning. I work hard to beat this out of my algebra students, even though it usually won’t trip them up; but my calculus students (if they haven’t gotten it beaten out) do trip over it, much like GenericThinker is doing here.
Mike
“Can’t do basic derivatives? Seriously?!? I’m for kicking the troll out. His bragging about mediocre mathematical accomplishments isn’t informative or entertaining to us readers.”
Did you look at his derivatives? “dy/dt = F(y) = Ay whose solution is y = e^(At)” How is e^(at) = dy/dt=ay Basic derivatives 101 d/dx e^x = e^x
“Solving
dy/dt = e^y
yields
y = -ln(C—t)”
again dy/dt=e^y does not equal -ln(c-t) unless e is not the irrational constant that it is normally even if that it is the case the solution is still wrong… again refer to a basic derivative table...
So I am a troll because I point out errors? Ok, fine then I am a troll and will never come back. Thats interesting so you must be a saint for thinking these errors are the truth.
I apologize that I am not amusing you, but I am not a court jester like yourself.
Mediocre accomplishments hmm… well did you skip all of your bachelors work straight to grad school in mathematics? I would bet not. Don’t talk of mediocrity unless you can prove yourself above that standard. So I believe your credentials would be needed to prove that or some of your own superior accomplishments if you have any? I await eagerly.
I believe that GenericThinker is interpreting ‘dy/dt = e^y’ as instructions to take the derivative of e^y (with respect to y or t I’m not sure). This is an extreme (and extremely arrogant) case of a general problem in lower-level and non-major math education; students learn to treat ‘=’ as a generic verb (although here it’s more of a preposition) instead of a symbol with a specific meaning. I work hard to beat this out of my algebra students, even though it usually won’t trip them up; but my calculus students (if they haven’t gotten it beaten out) do trip over it, much like GenericThinker is doing here.