In practice, it’s impossible to create a voting method that elects S equally-weighted candidates without wasting some votes; typically at least somewhere between 1/2S and 1/(S+1) of them.
This is a bit hard to read. Maybe write instead of 1/2S and 1/(S+1) of them a formula that depends on the V the number of voters and that’s V/(2S) and V/(S+1).
Thanks, fixed. (A numerator of 1 gives an answer in dimensionless units of “fraction of voters”; using V gives units of voters. I tend to prefer the former but I agree that at first read the latter is more intuitive.)
This is a bit hard to read. Maybe write instead of 1/2S and 1/(S+1) of them a formula that depends on the V the number of voters and that’s V/(2S) and V/(S+1).
Thanks, fixed. (A numerator of 1 gives an answer in dimensionless units of “fraction of voters”; using V gives units of voters. I tend to prefer the former but I agree that at first read the latter is more intuitive.)