My head scratcher with teleporatation is what would happen to momentum? If a Nightcrawler (x-man telporting charater) type jumped off an airplane and teleported mid-drop, would he still continue moving afterwards? I’d assume so, but say he changed position, teleported upside down. Now what?
Basically, is momentum relative to an internal or external frame of reference?
I suspect the answer is, that isn’t a question because the premises are impossible. Just like you can’t divide by zero, you can’t multiply by impossible.
Energy and momentum conservation is a local law in Relativity. How such conservation laws-compliant Nightcrawler would land depends on the actual mechanism of teleportation. For example, if he is transformed into a neutrino beam for the duration of the transport, the necessary momentum and angular momentum can be imparted by whatever surrounds him at the points of departure and arrival. The airplane or the surrounding air will recoil a bit (or a lot), and so will whatever objects he brakes against upon arrival.
What are the units of energy-momentum? Momentum is massdisplacement/time, while energy is length^2mass/time^2, so the conversion ratio would have to have units of length^2/displacement-time. You can use some tricks to make it appear to have units of length/time (speed), but then you need to permit either momentum or energy to be negative.
Is the binding energy variable depending on velocity? Losing mass at rest does conserve momentum, while losing mass in motion does proportionately to the speed of the lost mass. (and notably, NOT depending on whether it was moving towards, away, or lateral to the observer- red/blue shift is irrelevant). Is the amount of energy observed to be released from a given atomic reaction variable depending on the speed of the reactants?
My head scratcher with teleporatation is what would happen to momentum? If a Nightcrawler (x-man telporting charater) type jumped off an airplane and teleported mid-drop, would he still continue moving afterwards? I’d assume so, but say he changed position, teleported upside down. Now what?
Basically, is momentum relative to an internal or external frame of reference? I suspect the answer is, that isn’t a question because the premises are impossible. Just like you can’t divide by zero, you can’t multiply by impossible.
Energy and momentum conservation is a local law in Relativity. How such conservation laws-compliant Nightcrawler would land depends on the actual mechanism of teleportation. For example, if he is transformed into a neutrino beam for the duration of the transport, the necessary momentum and angular momentum can be imparted by whatever surrounds him at the points of departure and arrival. The airplane or the surrounding air will recoil a bit (or a lot), and so will whatever objects he brakes against upon arrival.
I don’t think momentum is conserved in Relativity; how could it be, if mass and therefore inertia are not?
Energy-momentum is most emphatically conserved in relativity, just not energy and momentum separately.
What are the units of energy-momentum? Momentum is massdisplacement/time, while energy is length^2mass/time^2, so the conversion ratio would have to have units of length^2/displacement-time. You can use some tricks to make it appear to have units of length/time (speed), but then you need to permit either momentum or energy to be negative.
Is the binding energy variable depending on velocity? Losing mass at rest does conserve momentum, while losing mass in motion does proportionately to the speed of the lost mass. (and notably, NOT depending on whether it was moving towards, away, or lateral to the observer- red/blue shift is irrelevant). Is the amount of energy observed to be released from a given atomic reaction variable depending on the speed of the reactants?