There are two equal-sized groups of large numbers:
Prime numbers
Composite numbers without any easy factorization
… such that you can’t be expected to distinguish them in the allowed time.
The lottery works by picking at one of the numbers at random.
Omega’s algorithm: for each number in those groups, predict whether you would two-box (given the already-determined lottery number). In the set of prime numbers for which you one-box, and composite numbers for which you two-box, pick a number at random and show it to you (so if it predicts you always two-box, it’s sure to pick a composite number, etc.).
In that setup, if your algorithm is “if the number ends in 3, two-box, else one-box”, then Omega will just pick a random number among the composites ending in 3 and the primes ending in 1, 3, 7, or 9.
And if your algorithm is “If the number is the same as the lottery, two-box, else, one-box”, then yeah the chosen number will not be completely independent of the lottery number (Omega can only pick the lottery number if it’s composite, or if it makes a prediction error), but that looks independent enough for the spirit of the post.
A plausible setup:
There are two equal-sized groups of large numbers:
Prime numbers
Composite numbers without any easy factorization
… such that you can’t be expected to distinguish them in the allowed time.
The lottery works by picking at one of the numbers at random.
Omega’s algorithm: for each number in those groups, predict whether you would two-box (given the already-determined lottery number). In the set of prime numbers for which you one-box, and composite numbers for which you two-box, pick a number at random and show it to you (so if it predicts you always two-box, it’s sure to pick a composite number, etc.).
In that setup, if your algorithm is “if the number ends in 3, two-box, else one-box”, then Omega will just pick a random number among the composites ending in 3 and the primes ending in 1, 3, 7, or 9.
And if your algorithm is “If the number is the same as the lottery, two-box, else, one-box”, then yeah the chosen number will not be completely independent of the lottery number (Omega can only pick the lottery number if it’s composite, or if it makes a prediction error), but that looks independent enough for the spirit of the post.