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thomblake comments on
0 And 1 Are Not Probabilities
thomblake
4 May 2010 19:11 UTC
1
point
P(A&B)+P(A&~B)+P(~A&B)+P(~A&~B)=1
Isn’t the “1” above a probability?
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P(A&B)+P(A&~B)+P(~A&B)+P(~A&~B)=1
Isn’t the “1” above a probability?