Math is entirely conceptual. What’s different in a black hole is PHYSICS, so the math used to describe physics is different, but 2+2 is entirely unaffected by gravitation, however mighty.
In terms of quantum physics I’m a layman so forgive me if this is too simplistic or wrong, but I think I see a couple problems with the way you state it. 1) Once the situation is observed and the state is determined, it doesn’t get redetermined differently for different observers. Having an effect on reality is not the same as reality being subjective. 2) Quantum physics doesn’t actually care about intelligent “observers”. The reason “observing” something influences the state it is in is because at the quantum level you get information about things by how they interact with other things bounced off them, and those things effect the thing being observed. A way of thinking about is if there are a bunch of bottles in a dark room and you can only figure out where they are by throwing a baseball into the room. Each time you hit a bottle, you find out WHERE it was, but it’s no longer there because you just shattered it. Until you hit it, you only have a rough idea of its probability of being in any given spot. When you “Observe” it the state of the bottle changes, but it’s not something that you did by observing it but by the method you used to gain information about it.
I would not even say that physics is different in a black hole. In fact, I would strongly bet against it. What is true is that our best physical theories fail to give coherent results at the center of a black hole, but of course this does not mean the actual physics is different. One must not confuse the map and the territory.
The bottle shattering is unnecessary and possibly distracting. It seems to be enough that it is moved (ETA: unpredictably), for the relation you are trying to draw. (I think that may still be incomplete, but I will let someone wiser in the ways of QM weigh in there).
Math is entirely conceptual. What’s different in a black hole is PHYSICS, so the math used to describe physics is different, but 2+2 is entirely unaffected by gravitation, however mighty.
In terms of quantum physics I’m a layman so forgive me if this is too simplistic or wrong, but I think I see a couple problems with the way you state it. 1) Once the situation is observed and the state is determined, it doesn’t get redetermined differently for different observers. Having an effect on reality is not the same as reality being subjective. 2) Quantum physics doesn’t actually care about intelligent “observers”. The reason “observing” something influences the state it is in is because at the quantum level you get information about things by how they interact with other things bounced off them, and those things effect the thing being observed. A way of thinking about is if there are a bunch of bottles in a dark room and you can only figure out where they are by throwing a baseball into the room. Each time you hit a bottle, you find out WHERE it was, but it’s no longer there because you just shattered it. Until you hit it, you only have a rough idea of its probability of being in any given spot. When you “Observe” it the state of the bottle changes, but it’s not something that you did by observing it but by the method you used to gain information about it.
I would not even say that physics is different in a black hole. In fact, I would strongly bet against it. What is true is that our best physical theories fail to give coherent results at the center of a black hole, but of course this does not mean the actual physics is different. One must not confuse the map and the territory.
The bottle shattering is unnecessary and possibly distracting. It seems to be enough that it is moved (ETA: unpredictably), for the relation you are trying to draw. (I think that may still be incomplete, but I will let someone wiser in the ways of QM weigh in there).
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