With some helpful questions and commands (eg. “which was the last stone a given player took to win?” and “write out the full tree of every possible move of the game!”) it is able to solve it:
[..]
🧔‍♂️What if the players play to win?
🤖If both players play optimally to win, the game will unfold as follows:
Player 1 takes a stone from any cell (A, B, C, or D): 1.1. Player 1 does NOT take a neighboring stone (3 stones left):
sql Copy code 1.1.1. Player 2 takes the stone with two neighbors:
1.1.1.1. Player 2 does NOT take an additional stone (2 non-neighboring stones left): - Player 1 takes one stone (1 stone left). - Player 2 takes the last stone. Player 2 wins.
* Player 2 will choose this optimal move to win.
1.1.2. Player 2 takes a stone with one neighbor:
1.1.2.1. Player 2 does NOT take an additional stone (2 neighboring stones left): - Player 1 takes one stone and its neighbor (0 stones left). Player 1 wins.
1.1.2.2. Player 2 takes the neighboring stone (1 stone left): - Player 1 takes the last stone. Player 1 wins.
* Player 2 will avoid this option since it doesn’t lead to a win. Player 1 should avoid this option since it leads to a win for Player 2 if both players play optimally. 1.2. Player 1 takes a neighboring stone (2 stones left):
sql Copy code 1.2.1. Player 2 takes one stone:
1.2.1.1. Player 2 does NOT take an additional stone (1 stone left): - Player 1 takes the last stone. Player 1 wins.
1.2.1.2. Player 2 takes the neighboring stone (0 stones left): - Player 2 wins.
* Player 2 will choose this optimal move to win. Player 1 should choose this option because it forces Player 2 to react optimally. It doesn’t guarantee a win, but it’s the best option available. When both players play optimally to win, Player 2 has a winning strategy. Player 1 cannot guarantee a win, and the optimal moves for both players will result in a win for Player 2.
With some helpful questions and commands (eg. “which was the last stone a given player took to win?” and “write out the full tree of every possible move of the game!”) it is able to solve it: