No—it just means it can’t be perfect. A scanner that works 99.9999999% of the time is effectively indistinguishable from a 100% for the purpose of the problem. One that is 100% except in the presence of recursion is completely identical if we can’t construct such a scanner.
My prior is justified because a workable Omega of type 3 or 4 is harder for me to imagine than 1 or 2. Disagree? What would you do as a good Bayesian?
I would one-box, but I’d do so regardless of the method being used, unless I was confident I could bluff Omega (which would generally require Omega-level resources on my part). It’s just that I don’t think the exact implementation Omega uses (or even whether we know the method) actually matter.
No—it just means it can’t be perfect. A scanner that works 99.9999999% of the time is effectively indistinguishable from a 100% for the purpose of the problem. One that is 100% except in the presence of recursion is completely identical if we can’t construct such a scanner.
I would one-box, but I’d do so regardless of the method being used, unless I was confident I could bluff Omega (which would generally require Omega-level resources on my part). It’s just that I don’t think the exact implementation Omega uses (or even whether we know the method) actually matter.