How do you know? It’s a strong claim, and I don’t see why the math would necessarily work out that way. Once you aggregate preferences fully, there might still be one best solution, and then it would make sense to take it.
Obviously you do need a tie-breaking method for when there’s more than one, but that’s just an optimization detial of an optimizer; it doesn’t turn you into a satisficer instead.
How do you know? It’s a strong claim, and I don’t see why the math would necessarily work out that way. Once you aggregate preferences fully, there might still be one best solution, and then it would make sense to take it. Obviously you do need a tie-breaking method for when there’s more than one, but that’s just an optimization detial of an optimizer; it doesn’t turn you into a satisficer instead.