Mark Eichenlaub and Patrick LaVictoire point out on Facebook that if we let p=P(A|B) and q=P(B|A), there’s a bound P(A) ⇐ p/(p+q-pq), which is smaller than p/q.
Mark Eichenlaub and Patrick LaVictoire point out on Facebook that if we let p=P(A|B) and q=P(B|A), there’s a bound P(A) ⇐ p/(p+q-pq), which is smaller than p/q.