#3:
x→x+1x on x≥1 shortens all distances but is strictly monotonic.
#6: (the “show that if” condition follows from the property, the question is likely misstated)
The iteration is so long that it must visit an element twice. We can’t have a cycle in the order so the repetition must be immediate.
Thanks, I actually wanted to get rid of the earlier condition that f(x)≥x for all x, and I did that.
#3:
x→x+1x on x≥1 shortens all distances but is strictly monotonic.
#6: (the “show that if” condition follows from the property, the question is likely misstated)
The iteration is so long that it must visit an element twice. We can’t have a cycle in the order so the repetition must be immediate.
Thanks, I actually wanted to get rid of the earlier condition that f(x)≥x for all x, and I did that.