you mean the N’th root of 2 right?, which is what I called the null predictor and divided Scott predictions by in the code:
random_predictor = 0.5 ** len(y)
which is equivalent to 0.5N where N is the total number of predictions
you mean the N’th root of 2 right?, which is what I called the null predictor and divided Scott predictions by in the code:
which is equivalent to 0.5N where N is the total number of predictions