The new page will also resemble a random string composed of “0” and “1″, so this process will continue indefinitely.
I don’t think this is true: there will be patterns emerging, and anything that appeared randomly and looks slightly less than random will make future continuations even less random until the LLM converges to something full of patterns.
Another way to say it- if it was always outputting 50/50% for 0 and 1, and you were running the process indefinitely, it would necessarily go through a string of all zeros, and I don’t think you think it would output 50⁄50 for 0 and 1 with a string full of zeros as the prompt.
Randomness is not stable. Pseudorandom-looking bitstrings don’t remain pseudorandom-looking if you pick the continuation randomly enough times.
I don’t think this is true: there will be patterns emerging, and anything that appeared randomly and looks slightly less than random will make future continuations even less random until the LLM converges to something full of patterns.
Another way to say it- if it was always outputting 50/50% for 0 and 1, and you were running the process indefinitely, it would necessarily go through a string of all zeros, and I don’t think you think it would output 50⁄50 for 0 and 1 with a string full of zeros as the prompt.
Randomness is not stable. Pseudorandom-looking bitstrings don’t remain pseudorandom-looking if you pick the continuation randomly enough times.
Yep, but it’s statistically unlikely. It is easier for order to disappear than for order to emerge.