That now the possibilities (C) and (D) must sum up to almost 100%, much like probabilities (A), (B), (C) and (D) previously did?
I don’t think this is obvious. Since (E) is nonzero and unspecified, it might be significant once (A) and (B) are excluded. Probably after excluding (A) and (B), it would be worth spending some time fleshing out (E) a bit better.
In my case, the priors on (C) and (D) are so low I’d just as well include them in (E) from the outset.
I don’t think this is obvious. Since (E) is nonzero and unspecified, it might be significant once (A) and (B) are excluded. Probably after excluding (A) and (B), it would be worth spending some time fleshing out (E) a bit better.
In my case, the priors on (C) and (D) are so low I’d just as well include them in (E) from the outset.