Oh, I see what you mean now.
(Incidentally, Eliezer’s original objection can be resolved by taking logs. Suddenly although the ratios 102⁄100 and 100⁄102 are not symmetrical, log(102/100) and log(100/102) are.)
Oh, I see what you mean now.
(Incidentally, Eliezer’s original objection can be resolved by taking logs. Suddenly although the ratios 102⁄100 and 100⁄102 are not symmetrical, log(102/100) and log(100/102) are.)