(If PA is strong enough to prove what the agent will do, then PA + “A()=x” is only consistent for one particular action x, and the specific action x for which it is consistent will be up for grabs, depending upon which proof the inconsistency checker finds.)
Then you get spurious proofs of inconsistency :-)
(If PA is strong enough to prove what the agent will do, then PA + “A()=x” is only consistent for one particular action x, and the specific action x for which it is consistent will be up for grabs, depending upon which proof the inconsistency checker finds.)
Got it. Thank you!