Yes. I believe that is consistent with what I said.
“not((necessarily, for each thing) : has [x] → those [x] are such that P_1([x]))” is equivalent to, ” (it is possible that something) has [x], but those [x] are not such that P_1([x])”
not((necessarily, for each thing) : has [x] such that P_2([x]) → those [x] are such that P_1([x])) is equivalent to “(it is possible that something) has [x], such that P_2([x]), but those [x] are not sure that P_1([x])” .
The latter implies the former, as (A and B and C) implies (A and C), and so the latter is stronger, not weaker, than the former.
Yes. I believe that is consistent with what I said.
“not((necessarily, for each thing) : has [x] → those [x] are such that P_1([x]))”
is equivalent to, ” (it is possible that something) has [x], but those [x] are not such that P_1([x])”
not((necessarily, for each thing) : has [x] such that P_2([x]) → those [x] are such that P_1([x]))
is equivalent to “(it is possible that something) has [x], such that P_2([x]), but those [x] are not sure that P_1([x])” .
The latter implies the former, as (A and B and C) implies (A and C), and so the latter is stronger, not weaker, than the former.
Right?