Wasn’t Löb’s theorem ∀ A (Provable(Provable(A) → A) → Provable(A))? So you get Provable(⊥) directly, rather than passing through ⊥ first. This is good, as, of course, ⊥ is always false, even if it is provable.
You’re right, I mixed it up. Edited the comment.
Wasn’t Löb’s theorem ∀ A (Provable(Provable(A) → A) → Provable(A))? So you get Provable(⊥) directly, rather than passing through ⊥ first. This is good, as, of course, ⊥ is always false, even if it is provable.
You’re right, I mixed it up. Edited the comment.