The point I’m making is that there is an additional parameter in the equation: your probability that cryonics is possible independent of that source. This needn’t be epsilon any more than the expectation of the lottery value need be epsilon.
I agree. That’s why I said so previously =P
The point I’m making is that there is an additional parameter in the equation: your probability that cryonics is possible independent of that source. This needn’t be epsilon any more than the expectation of the lottery value need be epsilon.
I agree. That’s why I said so previously =P